0.01x^2+0.05x-33=0

Solution for 0.01x^2+0.05x-33=0 equation:

0.01x^2+0.05x-33=0

a = 0.01; b = 0.05; c = -33;
Δ = b2-4ac
Δ = 0.052-4·0.01·(-33)
Δ = 1.3225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.05)-\sqrt{1.3225}}{2*0.01}=\frac{-0.05-\sqrt{1.3225}}{0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.05)+\sqrt{1.3225}}{2*0.01}=\frac{-0.05+\sqrt{1.3225}}{0.02}
$